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Chapter 4 Structure Of The Atom
Building upon the understanding from Chapter 3 that atoms and molecules are the fundamental constituents of matter, we delve deeper into the atom itself. While Dalton's atomic theory proposed that atoms are indivisible, scientific discoveries later revealed that atoms are, in fact, divisible and are composed of smaller, sub-atomic particles. This chapter explores the experimental evidence that led to the discovery of these particles and the models proposed to describe how they are arranged within an atom. Understanding the structure of the atom is crucial to explain the diverse properties of different elements and how they combine.
Charged Particles in Matter
Evidence suggesting that atoms are not indivisible came from studies of electricity, particularly static electricity. Simple activities like rubbing a comb through dry hair or rubbing a glass rod with a silk cloth demonstrate that objects can become electrically charged through friction. Since these charges are generated from the material itself, it implies that the atoms constituting the material must contain charged particles.
By the late 19th century, scientists were actively investigating these charged particles. Through experiments involving the passage of electricity through gases at low pressure (discharge tube experiments), the presence of sub-atomic particles was revealed.
- **Electrons:** J.J. Thomson, through his cathode ray experiments (where particles streamed from the negative electrode or cathode), identified negatively charged particles within atoms. He named them electrons, symbolized as 'e⁻'. Electrons have a very small mass, considered negligible compared to a proton (approximately 1/2000th the mass of a hydrogen atom), and carry a charge of minus one (-1 unit).
- **Protons:** Even before the electron was fully characterized, E. Goldstein discovered new radiations in gas discharge experiments in 1886, which he called **canal rays**. These rays traveled in the opposite direction to the cathode rays and were positively charged. This led to the discovery of the proton, symbolized as 'p⁺'. A proton has a charge equal in magnitude but opposite in sign to that of an electron (+1 unit). Its mass is approximately 2000 times that of an electron, close to the mass of a hydrogen atom (taken as 1 unit).
These discoveries suggested that atoms were composed of protons (positive charge, significant mass) and electrons (negative charge, negligible mass). Since atoms are generally electrically neutral, it was inferred that the number of positive charges (protons) must balance the number of negative charges (electrons) in a neutral atom. The question then arose: how were these charged particles arranged within the atom?
Question 1. What are canal rays?
Answer:
Canal rays are positively charged radiations discovered by E. Goldstein in 1886 during gas discharge experiments. They travel in the opposite direction to the cathode rays and led to the discovery of the proton. They were called canal rays because they passed through the perforations (channels) in the cathode.
Question 2. If an atom contains one electron and one proton, will it carry any charge or not?
Answer:
An atom containing one electron (charge -1) and one proton (charge +1) will be electrically neutral because the magnitude of the positive charge is equal to the magnitude of the negative charge, and they cancel each other out (+1 + (-1) = 0).
The Structure Of An Atom
The discovery of electrons and protons within the atom contradicted Dalton's idea of an indivisible atom. This prompted scientists to propose various models to explain the internal structure of the atom.
Thomson’s Model Of An Atom
J.J. Thomson proposed one of the first models for the structure of an atom in 1898. His model is often compared to a Christmas pudding or a watermelon.
According to Thomson's model:
- An atom is considered to be a **sphere of uniformly distributed positive charge**.
- The **electrons are embedded** within this positively charged sphere, like currants in a Christmas pudding or seeds in a watermelon.
- The magnitude of the negative charges (from electrons) is **equal to the magnitude of the positive charge** in the sphere. This makes the atom as a whole electrically neutral.
Thomson's model successfully explained the overall neutrality of the atom. However, it could not explain the results of later experiments, particularly Rutherford's alpha-particle scattering experiment, which indicated that the positive charge was concentrated in a very small region, not spread uniformly.
Rutherford’s Model Of An Atom
Ernest Rutherford, a student of J.J. Thomson, conducted experiments to investigate the arrangement of electrons within the atom. In 1911, he performed his famous **alpha-particle scattering experiment**.
In this experiment:
- A beam of fast-moving **alpha ($\alpha$) particles** (which are positively charged helium nuclei, ⁴₂He²⁺, with a mass of 4 u) was directed at a very **thin gold foil** (about 1000 atoms thick). Gold was chosen because it is highly malleable and could be made into an extremely thin sheet.
- A screen was placed around the gold foil to detect the deflected $\alpha$-particles.
- Based on Thomson's model (where positive charge is spread out), Rutherford expected the heavy, fast-moving $\alpha$-particles to pass straight through the thin gold foil with only minor deflections, as the positive charge would not be concentrated enough to cause large deviations.
However, the experimental results were surprisingly different:
- Most of the $\alpha$-particles ($\approx 99.9\%$) **passed straight through** the gold foil without any deflection.
- Some $\alpha$-particles were deflected by **small angles**.
- A very few $\alpha$-particles (about 1 in 12,000) were deflected back by nearly **180°** (appeared to rebound).
These unexpected results led Rutherford to draw the following conclusions about the structure of the atom:
- Since most $\alpha$-particles passed straight through, most of the space inside the atom must be **empty**.
- The deflection of some particles, especially the rare large-angle deflections and rebounds, indicated that the **positive charge** and most of the **mass** of the atom are concentrated in a very **small volume** at the centre. A direct collision between a positively charged $\alpha$-particle and this concentrated positive mass caused the large deflections and rebounds.
- This small, dense, positively charged region at the centre of the atom was named the **nucleus**.
Based on these conclusions, Rutherford proposed the **Nuclear Model of the Atom**:
- An atom has a tiny, positively charged **nucleus** at its centre, which contains nearly all the mass of the atom.
- The **electrons revolve** around the nucleus in well-defined circular paths (orbits).
- The size of the nucleus is extremely small compared to the overall size of the atom (the radius of the atom is about $10^5$ times larger than the radius of the nucleus).
Drawbacks of Rutherford’s Model:
Rutherford's model faced a major challenge regarding the stability of the atom. According to classical electromagnetic theory, a charged particle (like an electron) moving in a circular orbit around another charged particle (the nucleus) should continuously radiate energy. If the revolving electrons lost energy, they would spiral inwards and eventually crash into the nucleus. This would make the atom highly unstable and cause matter to collapse, which contradicts the observed stability of atoms.
Bohr’s Model Of Atom
To address the instability issue in Rutherford's model, Neils Bohr refined the atomic model in 1913. He proposed the following postulates for his model:
- Only certain special orbits, known as **discrete orbits** or stationary states, are allowed for electrons inside the atom.
- While revolving in these discrete orbits, electrons **do not radiate energy**. Each discrete orbit is associated with a fixed energy level.
These orbits or shells are also called **energy levels** or **energy shells**. They are designated by the letters K, L, M, N, ... or by the principal quantum numbers, n = 1, 2, 3, 4, ... respectively, starting from the orbit closest to the nucleus (n=1 is the K shell, n=2 is the L shell, and so on).
Neutrons
In 1932, James Chadwick discovered another sub-atomic particle that was also located in the nucleus. This particle was electrically neutral (had no charge) and had a mass very close to that of a proton. It was named the **neutron**, symbolized as 'n'.
Neutrons are present in the nucleus of all atoms, with the sole exception of hydrogen-1 (protium), which has only a proton in its nucleus. Along with protons, neutrons are collectively called **nucleons** because they reside in the nucleus.
The discovery of neutrons explained why the mass of an atom was often greater than the total mass of its protons alone. The mass of an atom is therefore the sum of the masses of the protons and neutrons in its nucleus. For example, a carbon atom with 6 protons and 6 neutrons has a mass of approximately $6 \text{ u} + 6 \text{ u} = 12 \text{ u}$. An aluminium atom with 13 protons and 14 neutrons has a mass of approximately $13 \text{ u} + 14 \text{ u} = 27 \text{ u}$.
Question 1. Name the three sub-atomic particles of an atom.
Answer:
The three main sub-atomic particles of an atom are:
- Electrons (negatively charged)
- Protons (positively charged)
- Neutrons (no charge)
Question 2. Helium atom has an atomic mass of 4 u and two protons in its nucleus. How many neutrons does it have?
Answer:
The mass number (approximately equal to atomic mass in u) is the sum of the number of protons and neutrons.
Mass number of Helium $\approx$ Atomic mass = 4 u.
Number of protons = 2.
Mass number = Number of protons + Number of neutrons
4 = 2 + Number of neutrons
Number of neutrons = 4 - 2 = 2.
Therefore, a helium atom has 2 neutrons.
How Are Electrons Distributed In Different Orbits (Shells)?
The distribution of electrons into the discrete energy levels or shells around the nucleus was explained by Bohr and Bury. Specific rules govern how electrons fill these shells:
- The maximum number of electrons that can be accommodated in any given shell is given by the formula $\mathbf{2n^2}$, where 'n' is the number of the orbit or energy level (n=1 for K shell, n=2 for L shell, n=3 for M shell, etc.).
- Based on this rule:
- K shell (n=1) can hold a maximum of $2 \times 1^2 = 2 \times 1 = 2$ electrons.
- L shell (n=2) can hold a maximum of $2 \times 2^2 = 2 \times 4 = 8$ electrons.
- M shell (n=3) can hold a maximum of $2 \times 3^2 = 2 \times 9 = 18$ electrons.
- N shell (n=4) can hold a maximum of $2 \times 4^2 = 2 \times 16 = 32$ electrons, and so on.
- The **outermost shell** of an atom can accommodate a maximum of **8 electrons** (the octet rule, important for chemical stability). This rule applies even if the $2n^2$ formula would allow more (e.g., for the M shell, the maximum is 18, but it behaves as the outermost shell with a capacity of 8 for elements up to atomic number 18).
- Shells are filled in a **step-wise manner**. Inner shells must be filled or nearly filled before electrons can occupy the outer shells. Electrons first occupy the lowest energy levels (shells) available.
These rules determine the **electronic configuration** of an atom, which describes how its electrons are distributed in the different energy shells. Electrons in the outermost shell are called **valence electrons**, and they are crucial in determining an element's chemical properties and combining capacity.
Figure 4.4 in the text shows schematic diagrams illustrating the electronic configuration of the first eighteen elements. Table 4.1 provides the composition (protons, neutrons, electrons) and electron distribution for these elements.
Question 1. Write the distribution of electrons in carbon and sodium atoms.
Answer:
From Table 4.1 or knowing their atomic numbers:
Carbon (C): Atomic number = 6. A neutral carbon atom has 6 electrons. The electron distribution is:
- K shell (n=1): Maximum capacity is 2. Contains 2 electrons.
- L shell (n=2): Remaining electrons = 6 - 2 = 4. This shell can hold up to 8, so it contains 4 electrons.
Electronic configuration of Carbon: 2, 4.
Sodium (Na): Atomic number = 11. A neutral sodium atom has 11 electrons. The electron distribution is:
- K shell (n=1): Maximum capacity is 2. Contains 2 electrons.
- L shell (n=2): Maximum capacity is 8. Contains 8 electrons. (Inner shells are filled first).
- M shell (n=3): Remaining electrons = 11 - 2 - 8 = 1. This shell can hold up to 18, so it contains 1 electron.
Electronic configuration of Sodium: 2, 8, 1.
Question 2. If K and L shells of an atom are full, then what would be the total number of electrons in the atom?
Answer:
The maximum number of electrons in the K shell (n=1) is $2 \times 1^2 = 2$.
The maximum number of electrons in the L shell (n=2) is $2 \times 2^2 = 8$.
If both the K and L shells are full, the total number of electrons in the atom is the sum of the maximum capacities of these shells.
Total electrons = (Maximum electrons in K) + (Maximum electrons in L)
Total electrons = 2 + 8 = 10.
A neutral atom with 10 electrons is the element Neon (atomic number 10).
Valency
The **valency** of an element is its combining capacity – its ability to form chemical bonds with other atoms. This combining capacity is determined by the number of **valence electrons**, which are the electrons present in the outermost shell of an atom.
Atoms tend to react and form chemical bonds to achieve a stable electron configuration in their outermost shell. The most stable configuration is typically an **octet** (8 electrons) in the outermost shell, or a **duplet** (2 electrons) for very light elements like Helium. Atoms achieve this stability by gaining, losing, or sharing valence electrons.
The number of electrons that an atom loses, gains, or shares to attain a stable outermost shell (usually an octet) represents its valency.
- Elements with a completely filled outermost shell (like noble gases - Neon, Argon with 8 valence electrons, or Helium with 2) are chemically inert, meaning they have a combining capacity or valency of **zero**.
- Elements with 1, 2, or 3 valence electrons (like Hydrogen, Lithium, Sodium, Magnesium, Aluminium) tend to **lose** these electrons to achieve a stable inner shell (which is now the outermost and filled). The number of electrons lost equals their valency. Thus, the valency of H, Li, Na is 1; Mg is 2; Al is 3.
- Elements with 5, 6, or 7 valence electrons (like Nitrogen, Oxygen, Fluorine, Chlorine) tend to **gain** electrons to complete their octet. Their valency is calculated by subtracting the number of valence electrons from 8.
- Fluorine has 7 valence electrons. Valency = 8 - 7 = 1. Fluorine tends to gain 1 electron.
- Oxygen has 6 valence electrons. Valency = 8 - 6 = 2. Oxygen tends to gain 2 electrons.
- Nitrogen has 5 valence electrons. Valency = 8 - 5 = 3. Nitrogen tends to gain 3 electrons.
- Elements with 4 valence electrons (like Carbon, Silicon) tend to **share** electrons to achieve a stable configuration, and their valency is typically 4.
Thus, valency provides a quantitative measure of an element's tendency to combine with other elements. The valencies of the first eighteen elements are listed in Table 4.1.
Question 1. How will you find the valency of chlorine, sulphur and magnesium?
Answer:
First, find the electronic configuration of each element:
- Chlorine (Cl): Atomic number = 17. Electronic configuration: 2, 8, 7. It has 7 valence electrons. To achieve an octet, it needs to gain 1 electron (8 - 7 = 1). Its valency is **1**.
- Sulphur (S): Atomic number = 16. Electronic configuration: 2, 8, 6. It has 6 valence electrons. To achieve an octet, it needs to gain 2 electrons (8 - 6 = 2). Its valency is **2**.
- Magnesium (Mg): Atomic number = 12. Electronic configuration: 2, 8, 2. It has 2 valence electrons. It is easier for it to lose these 2 electrons to achieve a stable configuration (the now-outer L shell with 8 electrons). The number of electrons lost is 2. Its valency is **2**.
Atomic Number And Mass Number
Two key numbers are used to describe the composition of an atom: the atomic number and the mass number.
Atomic Number
The **atomic number (Z)** of an element is equal to the **total number of protons** present in the nucleus of an atom of that element. The number of protons is unique to each element and defines its identity. For example, every atom with 6 protons is a carbon atom (Z=6), and every atom with 1 proton is a hydrogen atom (Z=1).
In a neutral atom, the number of electrons is equal to the number of protons, so the atomic number also indicates the number of electrons in a neutral atom.
Mass Number
The **mass number (A)** of an atom is the **sum of the total number of protons and neutrons** (nucleons) present in its nucleus. Since protons and neutrons have significant mass compared to electrons, the mass number essentially represents the total number of particles contributing significantly to the atom's mass, which is concentrated in the nucleus.
Mass Number (A) = Number of protons (Z) + Number of neutrons (n)
An atom is typically represented using the following notation:
$$ \text{_Z^A X} $$Where:
- $\text{X}$ is the symbol of the element.
- $\text{A}$ is the Mass Number (written as a superscript on the left).
- $\text{Z}$ is the Atomic Number (written as a subscript on the left).
For example, Nitrogen is represented as $^{14}_7\text{N}$. This means Nitrogen has an atomic number (Z) of 7 (7 protons) and a mass number (A) of 14 (7 protons + 7 neutrons). Sulfur is $^{32}_{16}\text{S}$, meaning Z=16 (16 protons) and A=32 (16 protons + 16 neutrons).
Question 1. If number of electrons in an atom is 8 and number of protons is also 8, then (i) what is the atomic number of the atom? and (ii) what is the charge on the atom?
Answer:
(i) The atomic number of an atom is equal to the number of protons in its nucleus. Since the number of protons is 8, the atomic number (Z) of the atom is **8**.
(ii) The charge on the atom is the sum of the charges of its protons and electrons. Number of protons = 8 (each with +1 charge), total positive charge = +8. Number of electrons = 8 (each with -1 charge), total negative charge = -8. Total charge = (+8) + (-8) = **0**. The atom is electrically neutral.
Question 2. With the help of Table 4.1, find out the mass number of oxygen and sulphur atom.
Answer:
From Table 4.1:
- Oxygen (O): Atomic number (Protons) = 8. Number of neutrons = 8. Mass Number (A) = Protons + Neutrons = 8 + 8 = **16**.
- Sulphur (S): Atomic number (Protons) = 16. Number of neutrons = 16. Mass Number (A) = Protons + Neutrons = 16 + 16 = **32**.
Isotopes
In nature, some elements exist as atoms that have the same atomic number (meaning they belong to the same element) but different mass numbers. These are called **isotopes**.
Isotopes are atoms of the same element that have the same number of protons (same atomic number, Z) but different numbers of neutrons, resulting in different mass numbers (A).
Examples of isotopes:
- **Hydrogen:** Exists in three isotopic forms:
- Protium ($^1_1\text{H}$): 1 proton, 0 neutrons, A=1
- Deuterium ($^2_1\text{H}$ or D): 1 proton, 1 neutron, A=2
- Tritium ($^3_1\text{H}$ or T): 1 proton, 2 neutrons, A=3
- **Carbon:** Common isotopes are $^{12}_6\text{C}$ (6 protons, 6 neutrons) and $^{14}_6\text{C}$ (6 protons, 8 neutrons).
- **Chlorine:** Common isotopes are $^{35}_{17}\text{Cl}$ (17 protons, 18 neutrons) and $^{37}_{17}\text{Cl}$ (17 protons, 20 neutrons).
Since isotopes of an element have the same number of electrons and the same electronic configuration, they exhibit very **similar chemical properties**. However, due to the difference in the number of neutrons and hence mass, their **physical properties** (like density, melting point, boiling point) can be slightly different.
Many elements found in nature are mixtures of different isotopes. The atomic mass of such an element is taken as the **average atomic mass**, which is a weighted average based on the relative abundance (percentage) of each isotope in nature.
For example, chlorine exists as $^{35}\text{Cl}$ with approximately 75% abundance and $^{37}\text{Cl}$ with approximately 25% abundance.
Average atomic mass of Chlorine = $\left( \text{Mass of }^{35}\text{Cl} \times \frac{\%\text{ Abundance of }^{35}\text{Cl}}{100} \right) + \left( \text{Mass of }^{37}\text{Cl} \times \frac{\%\text{ Abundance of }^{37}\text{Cl}}{100} \right)$
Average atomic mass of Chlorine = $\left( 35 \text{ u} \times \frac{75}{100} \right) + \left( 37 \text{ u} \times \frac{25}{100} \right)$
Average atomic mass of Chlorine = $\left( 35 \times \frac{3}{4} \right) + \left( 37 \times \frac{1}{4} \right) \text{ u}$
Average atomic mass of Chlorine = $\frac{105}{4} + \frac{37}{4} \text{ u} = \frac{142}{4} \text{ u} = 35.5 \text{ u}$
This calculated average atomic mass of 35.5 u is what is listed for chlorine. It's important to note that no single chlorine atom has a mass of 35.5 u; this is a statistical average over a large sample of chlorine atoms.
Applications of Isotopes:
While isotopes of an element behave chemically similarly, some isotopes have specific physical properties (like radioactivity) that make them useful in various applications:
- An isotope of **Uranium** ($^{235}\text{U}$) is used as fuel in nuclear reactors for generating electricity.
- An isotope of **Cobalt** ($^{60}\text{Co}$) is used in the treatment of cancer (radiotherapy).
- An isotope of **Iodine** ($^{131}\text{I}$) is used in the treatment of goitre (a thyroid condition) and as a tracer in medical imaging.
- The isotope $^{14}\text{C}$ is used in **carbon dating** to estimate the age of ancient organic materials.
Isobars
Another term related to atomic composition is **isobars**.
Isobars are atoms of different elements that have different atomic numbers (Z) but the same mass number (A).
This means isobars have a different number of protons (since Z is different) and thus belong to different elements. However, the total number of nucleons (protons + neutrons) is the same in their nucleus.
Examples of isobars:
- **Calcium** ($^{40}_{20}\text{Ca}$): Z=20, A=40 (20 protons + 20 neutrons)
- **Argon** ($^{40}_{18}\text{Ar}$): Z=18, A=40 (18 protons + 22 neutrons)
Calcium and Argon are different elements (different Z) but have the same mass number (A=40). Isobars have different chemical properties because they are different elements with different numbers of electrons.
Question 1. For the symbol H, D and T tabulate three sub-atomic particles found in each of them.
Answer:
H, D, and T represent the three isotopes of Hydrogen: Protium ($^1_1\text{H}$), Deuterium ($^2_1\text{H}$), and Tritium ($^3_1\text{H}$). The atomic number (Z) for all is 1, meaning they all have 1 proton and, in a neutral atom, 1 electron. The mass number (A) is Protons + Neutrons.
| Isotope Symbol | Number of Protons (Z) | Number of Electrons (in neutral atom) | Mass Number (A) | Number of Neutrons (A - Z) |
|---|---|---|---|---|
| H ($^1_1\text{H}$) | 1 | 1 | 1 | 1 - 1 = 0 |
| D ($^2_1\text{H}$) | 1 | 1 | 2 | 2 - 1 = 1 |
| T ($^3_1\text{H}$) | 1 | 1 | 3 | 3 - 1 = 2 |
Question 2. Write the electronic configuration of any one pair of isotopes and isobars.
Answer:
Isotopes: Let's take the isotopes of Carbon, $^{12}_6\text{C}$ and $^{14}_6\text{C}$.
For both isotopes, the atomic number (Z) is 6. This means a neutral atom of either isotope has 6 protons and 6 electrons.
The electronic configuration for an atom with 6 electrons is determined by filling the shells according to the rules (2 electrons in K shell, remaining in L shell).
- K shell (n=1): 2 electrons (Max capacity 2)
- L shell (n=2): 6 - 2 = 4 electrons (Max capacity 8)
The electronic configuration for both $^{12}_6\text{C}$ and $^{14}_6\text{C}$ is **2, 4**.
Isobars: Let's take the isobars $^{40}_{20}\text{Ca}$ and $^{40}_{18}\text{Ar}$.
- Calcium ($^{40}_{20}\text{Ca}$): Atomic number (Z) = 20. A neutral Ca atom has 20 electrons.
- K shell (n=1): 2 electrons
- L shell (n=2): 8 electrons
- M shell (n=3): 8 electrons (Outer shell rule applies here for stability up to Ar, then N shell starts filling)
- N shell (n=4): 20 - 2 - 8 - 8 = 2 electrons
Electronic configuration of Calcium: **2, 8, 8, 2**.
- Argon ($^{40}_{18}\text{Ar}$): Atomic number (Z) = 18. A neutral Ar atom has 18 electrons.
- K shell (n=1): 2 electrons
- L shell (n=2): 8 electrons
- M shell (n=3): 18 - 2 - 8 = 8 electrons
Electronic configuration of Argon: **2, 8, 8**.
Note that isobars, being different elements (different atomic numbers), have different electronic configurations.
Intext Questions
Page No. 39
Question 1. What are canal rays?
Answer:
Question 2. If an atom contains one electron and one proton, will it carry any charge or not?
Answer:
Page No. 41
Question 1. On the basis of Thomson’s model of an atom, explain how the atom is neutral as a whole.
Answer:
Question 2. On the basis of Rutherford’s model of an atom, which subatomic particle is present in the nucleus of an atom?
Answer:
Question 3. Draw a sketch of Bohr’s model of an atom with three shells.
Answer:
Question 4. What do you think would be the observation if the $ \alpha $-particle scattering experiment is carried out using a foil of a metal other than gold?
Answer:
Question 1. Name the three sub-atomic particles of an atom.
Answer:
Question 2. Helium atom has an atomic mass of 4 u and two protons in its nucleus. How many neutrons does it have?
Answer:
Page No. 42
Question 1. Write the distribution of electrons in carbon and sodium atoms.
Answer:
Question 2. If K and L shells of an atom are full, then what would be the total number of electrons in the atom?
Answer:
Page No. 44
Question 1. How will you find the valency of chlorine, sulphur and magnesium?
Answer:
Question 1. If number of electrons in an atom is 8 and number of protons is also 8, then (i) what is the atomic number of the atom? and (ii) what is the charge on the atom?
Answer:
Question 2. With the help of Table 4.1, find out the mass number of oxygen and sulphur atom.
Answer:
Page No. 45
Question 1. For the symbol H, D and T tabulate three sub-atomic particles found in each of them.
Answer:
Question 2. Write the electronic configuration of any one pair of isotopes and isobars.
Answer:
Exercises
Question 1. Compare the properties of electrons, protons and neutrons.
Answer:
Question 2. What are the limitations of J.J. Thomson’s model of the atom?
Answer:
Question 3. What are the limitations of Rutherford’s model of the atom?
Answer:
Question 4. Describe Bohr’s model of the atom.
Answer:
Question 5. Compare all the proposed models of an atom given in this chapter.
Answer:
Question 6. Summarise the rules for writing of distribution of electrons in various shells for the first eighteen elements.
Answer:
Question 7. Define valency by taking examples of silicon and oxygen.
Answer:
Question 8. Explain with examples (i) Atomic number, (ii) Mass number, (iii) Isotopes and iv) Isobars. Give any two uses of isotopes.
Answer:
Question 9. $Na^+$ has completely filled K and L shells. Explain.
Answer:
Question 10. If bromine atom is available in the form of, say, two isotopes $^{\text{79}}_{\text{35}} Br$ (49.7%) and $^{\text{81}}_{\text{35}} Br$ (50.3%), calculate the average atomic mass of bromine atom.
Answer:
Question 11. The average atomic mass of a sample of an element X is 16.2 u. What are the percentages of isotopes $^{\text{16}}_{\text{8}} X$ and $^{\text{18}}_{\text{8}} X$ in the sample?
Answer:
Question 12. If $Z = 3$, what would be the valency of the element? Also, name the element.
Answer:
Question 13. Composition of the nuclei of two atomic species X and Y are given as under
$$ \begin{array}{l|cc} & X & Y \\ \hline \text{Protons} & 6 & 6 \\ \text{Neutrons} & 6 & 8 \end{array} $$
Give the mass numbers of X and Y. What is the relation between the two species?
Answer:
Question 14. For the following statements, write T for True and F for False.
(a) J.J. Thomson proposed that the nucleus of an atom contains only nucleons.
(b) A neutron is formed by an electron and a proton combining together. Therefore, it is neutral.
(c) The mass of an electron is about $\frac{1}{2000}$ times that of proton.
(d) An isotope of iodine is used for making tincture iodine, which is used as a medicine.
Answer:
Question 15. Rutherford’s $\alpha$-particle scattering experiment was responsible for the discovery of
(a) Atomic Nucleus
(b) Electron
(c) Proton
(d) Neutron
Answer:
Question 16. Isotopes of an element have
(a) the same physical properties
(b) different chemical properties
(c) different number of neutrons
(d) different atomic numbers.
Answer:
Question 17. Number of valence electrons in $Cl^-$ ion are:
(a) 16
(b) 8
(c) 17
(d) 18
Answer:
Question 18. Which one of the following is a correct electronic configuration of sodium?
(a) 2,8
(b) 8,2,1
(c) 2,1,8
(d) 2,8,1.
Answer:
Question 19. Complete the following table.
| Atomic Number | Mass Number | Number of Neutrons | Number of Protons | Number of Electrons | Name of the Atomic Species |
|---|---|---|---|---|---|
| 9 | - | 10 | - | - | - |
| 16 | 32 | - | - | - | Sulphur |
| - | 24 | - | 12 | - | - |
| - | 2 | - | 1 | - | - |
| - | 1 | 0 | 1 | 0 | - |
Answer: